Question

Write an equation in slope-intercept form of the line that passes through the given point and is parallel to the graph of the given equation.

(-6, - 8); y= - 3x + 3
Write an equation for the line in slope-intercept form
(Simplify your answer. Use integers or fractions for any numbers in the equation.)​

Answer 1

The Answer is: y = -3x - 26

Explanation:

Given point: (-6, -8)

Given equation:

y = -3x + 3, the slope m = -3

A parallel line has the same slope, m = 3. Use the point slope form and substitute in the point and the slope:

y - y1 = m(x - x1)

y - (-8) = -3(x - (-6))

y + 8 = -3x - 18

y = -3x - 18 - 8

y = -3x - 26

Proof - use the point (-6, -8):

f(x) = -3x -26

f(-6) = -3(-6) - 26

= 18 - 26 = -8, giving (-6, -8)