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Train cars are coupled together by being bumped into one another. Suppose two loaded cars are moving toward one another, the first having a mass of 1.50×10 5 kg and a velocity of 0.30 m/s i, and the second having a mass of 2×10 5 kg and a velocity of −0.12m/s i. What is the energy lost in this inelastic collision?

User Ezanker
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1 Answer

2 votes

Answer:7.56 kJ

Step-by-step explanation:

mass of first train
m_1=1.50* 10^5 kg

mass of second train
m_2=2* 10^5 kg

velocity of first train
v_1=0.3\hat{i} m/s

velocity of second train
v_2=-0.12 \hat{i} m/s

conserving momentum


m_1v_1+m_2v_2=(m_1+m_2)v


v=(m_1v_1+m_2v_2)/(m_1+m_2)


v=(.50* 10^5* 0.3-2* 10^5* 0.12)/((1.5+2)\cdot 10^5)


v=0.06 m/s

Energy Lost in Inelastic collision


=(m_1v_1^2)/(2)+(m_2v_2^2)/(2)-((m_1+m_2)v^2)/(2)


=(1.50* 10^5* 0.3^2)/(2)+(2* 10^5* (-0.12)^2)/(2)-(3.5* 10^5* 0.07^2)/(2)


=((0.135+0.0288-0.0126)* 10^5)/(2)


=(0.1512* 10^5)/(2)


=7.56 kJ

User Tatoline
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