Answer:
The proportion of trees greater than 5 inches is expected to be 0.25 of the total amount of trees.
Explanation:
In this problem we have a normal ditribution with mean of 4.0 in and standard deviation of 1.5 in.
The proportion of the trees that are expected to have diameters greater than 5 inches is equal to the probability of having a tree greater than 5 inches.
We can calculate the z value for x=5 in and then look up in a standard normal distribution table the probability of z.
![z=(x-\mu)/(\sigma)=(5-4)/(1.5)=0.67](https://img.qammunity.org/2020/formulas/mathematics/college/rwdcehe0hdkwpwvdj4et1ymtm4riw1usur.png)
The proportion of trees greater than 5 inches is expected to be 0.25 of the total amount of trees.