Question

What is the equation of a line that passes through the point (9, -3) and is parallel to the line whose equation is 2x-3y=6

Answer 1

Explanation:

2x-3y=6

-3y = -2x + 6

y = -2x/-3 + 6/ -3

y = 2x/3 - 2 {y =mx + c}

slope = 2/3

The required line's slope is also 2/3 as it is parallel to this line

Point(9, -3)

y -y1 = m(x-x1)

y - (-3) = 2/3 (x - 9)

y + 3 = 2x/3 - 2*9/3

y + 3 =2x/3 - 2*3

y + 3 = 2x/3 -6

y = 2x/3 - 6 - 3

y = 2x/3 - 9