Answer:
So after 7 year price of the laptop will be less than $1000
Explanation:
We have given price of the laptop is $4500
Its price is 80% of if its value in every next year
So depreciation rate = 100 - 80 =20%
For depreciation we know that

Here V is final value and P is present value
So


Taking log both side

n = 6.74
So after 6.74 year the price of the laptop will be less than $1000