Answer:
![√(118)\approx 10.86](https://img.qammunity.org/2020/formulas/mathematics/middle-school/36pg2g9dg77q1701b7tina8jxa5cyjto77.png)
![√(319)\approx 17.86](https://img.qammunity.org/2020/formulas/mathematics/middle-school/mlo29cispabaegfazcr3etpf9vc53ozxwx.png)
Explanation:
Consider the provided number.
We need to find the approximate value of
to the nearest hundredth.
First find two perfect squares that the irrational number falls between.
![100<118<121](https://img.qammunity.org/2020/formulas/mathematics/middle-school/9cdv5cngugwyjxbc1t6joqhl1oferruwsn.png)
118 is lying between 100 and 121, therefore the square root value of 118 will be somewhere between 10 and 11.
![√(100)<√(118)<√(121)](https://img.qammunity.org/2020/formulas/mathematics/middle-school/c10pyk3813evh5fewpia5qlz0lk9ziqt7y.png)
![10<√(118)<11](https://img.qammunity.org/2020/formulas/mathematics/middle-school/qyrkqk263x5tmqp0z6zs3y3j9z54voefo5.png)
118 is closer to 121 as compare to 100.
Therefore,
![√(118)\approx 10.86](https://img.qammunity.org/2020/formulas/mathematics/middle-school/36pg2g9dg77q1701b7tina8jxa5cyjto77.png)
Consider the number
![√(319)](https://img.qammunity.org/2020/formulas/mathematics/middle-school/uw70sb8plcyfdanv4vpmny2bw89mmcl1bo.png)
First find two perfect squares that the irrational number falls between.
![289<319<324](https://img.qammunity.org/2020/formulas/mathematics/middle-school/5hghgsi3ltvfiroqtwqssihzylkmk9aps1.png)
319 is lying between 289 and 324, therefore the square root value of 319 will be somewhere between 17 and 18.
![√(289)<√(319)<√(324)](https://img.qammunity.org/2020/formulas/mathematics/middle-school/6eukijq6akma84g6g8gulkaip6tqivt3e0.png)
![17<√(319)<18](https://img.qammunity.org/2020/formulas/mathematics/middle-school/ug8qepd8umzbz4oc5m39pxu5jablqbwnn5.png)
319 is closer to 324 as compare to 289.
Therefore,
![√(319)\approx 17.86](https://img.qammunity.org/2020/formulas/mathematics/middle-school/mlo29cispabaegfazcr3etpf9vc53ozxwx.png)