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In a​ five-card poker​ hand, what is the probability of being dealt exactly one ace and no picture cards​?
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In a​ five-card poker​ hand, what is the probability of being dealt exactly one ace and no picture cards​?

User Ebram
by
6.1k points

1 Answer

4 votes

Answer:

p = ((4C1)(12C0)(36C4))/(52C5)

Explanation:

p = ((4C1)(12C0)(36C4))/(52C5)

User MaLio
by
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