Find the derivative of the function f(x) = 6x^-3 + x^2 + 14.

asked Oct 24, 2020 103k views

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Answer:

Explanation:

f(x) = 6x^-3 + x^2 + 14.

note : (x^n)' = n x ^(n-1)

f'(x) = (6)(-3) x^-4 +2x= -18 x^-4 +2x

Mmw answered Oct 31, 2020

by Mmw

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