Question

53. • A convertible travels down a straight, level road at a

slow speed of 13 km/h. A person in the car throws a ball
with a speed of 3.6 m/s forward at an angle of 30° to the
horizontal. Where is the car when the ball lands?

Answer 1

The convertible will be ahead at a distance from its initial position, d = 1.336 m

Step-by-step explanation:

Given,

The speed of the convertible, v = 13 Km/h

= 3.61 m/s

A ball thrown with a speed, u = 3.6 m/s

The angle of the velocity of a ball formed with the horizontal, Φ = 30°

The time of flight of the projectile is given by the formula,

T = 2u sin Ф / g

= 2 x 3.6 x 0.5 / 9.8

= 0.37 s

The displacement of the car,

d = v x t

= 3.6 x 0.37

= 1.336 m

Hence, the convertible will be ahead at a distance from its initial position, d = 1.336 m