Question

What is the equation for a line that goes through (0,-1) and (3,1)

Answer 1

y=2/3x-1

Explanation:

m=(y2-y1)/(x2-x1)

m=(1-(-1))/(3-0)

m=(1+1)/3

m=2/3

y-y1=m(x-x1)

y-(-1)=2/3(x-0)

y+1=2/3(x)

y+1=2/3x

y=2/3x-1