1 Answer

Xbito · Answer 1 · 2020-07-13T04:56:48+0000

For this case we must solve the following equation:

$3x- \frac {1} {5} = x + \frac {1} {3}$

Subtracting "x" from both sides of the equation we have:

$3x-x- \frac {1} {5} = \frac {1} {3}\\2x- \frac {1} {5} = \frac {1} {3}$

Adding
$\frac {1} {5}$ to both sides of the equation we have:

$2x = \frac {1} {3} + \frac {1} {5}\\2x = \frac {5 + 3} {15}\\2x = \frac {8} {15}$

We divide between 2 on both sides of the equation:

$x = \frac {\frac {8} {15}} {2}\\x = \frac {8} {15 * 2}\\x = \frac {8} {30}\\x = \frac {4} {15}$

Thus, the solution of the equation is:

$x = \frac {4} {15}$

Answer:

$x = \frac {4} {15}$

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