Answer:
The woman's force was directed 59.22⁰ to the horizontal.
Step-by-step explanation:
Given;
work done by the woman, W = 236 J
distance through the load was moved, d = 24.4 m
applied force, F = 18.9 N
inclination of the force, = θ
The work done by the woman is calculated as;
W = Fdcosθ
Therefore, the woman's force was directed 59.22⁰ to the horizontal.