The quadratic factors of the given expression are (3x + 5) and (5x + 9).
SOLUTION:
Given, quadratic equation is 15x squared + 52x + 45
![\bold{\rightarrow 15 x^(2)+52 x+45}](https://img.qammunity.org/2020/formulas/mathematics/middle-school/ocrfa4ijicyt2haicp7ea5j8w1bso7l9g8.png)
We have to find the quadratic factors for the given quadratic expression.
Now, let us factorize the given expression.
![\begin{array}{l}\bold{\rightarrow 15 x^(2)+52 x+45} \\\\ \bold{\rightarrow 15 x^(2)+25 x+27 x+45} \\\\ \text{ (where 52x can be represented as the sum of 25x and 27x)} \\\\ \text{ Taking the common factors out of the braces } \\\\ \bold{\rightarrow 5 x(3 x+5)+9(3 x+5)} \\\\ \bold{\rightarrow(3 x+5)(5 x+9)}\end{array}](https://img.qammunity.org/2020/formulas/mathematics/middle-school/70gmmd55xluytmrtba1gk4elh5bksf610q.png)
Hence, the quadratic factors are (3x + 5) and (5x + 9).
Steps to factorise quadratic equation:
With the quadratic equation in this form:
![a x^(2)+b x+c=0](https://img.qammunity.org/2020/formulas/mathematics/middle-school/ohnayl9gp2jx71924lkcycicd9lnqn8fp4.png)
- Step 1: Find two numbers that multiply to give ac (in other words a times c), and add to give b.
- Step 2: Rewrite the middle with those numbers
- Step 3: Factor the first two and last two terms separately
- Step 4: If we've done this correctly, our two new terms should have a clearly visible common factor.