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A shopper in a supermarket pushes a loaded cart with a horizontal force of 11 N. The cart has a mass of 35 kg. The acceleration of gravity is 9.8 m/s 2 . Disregarding friction, how far will the cart move in 3.5 s, starting from rest? Answer in units of m.

User Tyreek
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1 Answer

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Answer:

s = 1.925 meters

Step-by-step explanation:

Given that,

Horizontal force acting on the cart, F = 11 N

Mass of the cart, m = 35 kg

To find,

Distance covered by the cart in 3.5 seconds if it starts from rest.

Solution,

As the cart is starting from rest, u = 0

Let x is the distance moved by the cart. It can be calculated using the second equation of motion as :


s=ut+(1)/(2)at^2

Since,
a=(F)/(m)


s=(1)/(2)* (F)/(m)* t^2


s=(1)/(2)* (11)/(35)* (3.5)^2

s = 1.925 meters

Therefore, the distance covered by the cart is 1.925 meters.

User Pavel Tupitsyn
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