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The coordinates of the endpoints of ST are (-2,3) and (3, y) respectively supposethe distance between s and t us 13 units.What values of life would satisfy the given condition?Justify your answer

User Sunil Dora
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1 Answer

1 vote

Answer:

The values of y would be -9 and 15

Explanation:

we know that

the formula to calculate the distance between two points is equal to


d=\sqrt{(y2-y1)^(2)+(x2-x1)^(2)}

we have


d=13\ units

S(-2,3) and T(3,y)

substitute the given values in the formula and solve for y


13=\sqrt{(y-3)^(2)+(3+2)^(2)}


13=\sqrt{(y-3)^(2)+25}

squared both sides


169=(y-3)^(2)+25


(y-3)^(2)=169-25


(y-3)^(2)=144

take square root both sides


y-3=(+/-)12


y=3(+/-)12


y=3(+)12=15


y=3(-)12=-9

therefore

The values of y would be -9 and 15

User Jaye Renzo Montejo
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