The distance between point A (-1, 3) and point B (-7, 3) is 6 units
Solution:
Given, two points are A(-1, 3) and (-7, 3)
We need to find the distance between above two points.
We know that distance between two points
is given as:
![d(P, Q)=\sqrt{\left(x_(2)-x_(1)\right)^(2)+\left(y_(2)-y_(1)\right)^(2)}](https://img.qammunity.org/2020/formulas/mathematics/middle-school/w7v0b2gyt7l38mo1sw6orwjtejt1g4p5oq.png)
![\text { here, } x_(1)=-1, y_(1)=3, x_(2)=-7 \text { and } y_(2)=3](https://img.qammunity.org/2020/formulas/mathematics/middle-school/tef3fvf3o19qfad53frkqgtn6lxrr4nfu1.png)
Substitute the values we get,
![\begin{array}{l}{\text { Distance }=\sqrt{((-7)-(-1))^(2)+(3-3)^(2)}} \\\\ {=\sqrt{(1-7)^(2)+(0)^(2)}=\sqrt{(-6)^(2)+0}} \\\\ {=√(36)=6}\end{array}](https://img.qammunity.org/2020/formulas/mathematics/middle-school/v68s9r1bt50en8y770psilqdnp51gctfkg.png)
Hence, the distance between two points is 6 units.