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Find the product. (–7t – 5v)(–4t – 3v)

A: 28t^2 + 15v^2

B: 28t^2 + 41tv + 15v^2

C: –11t – 8v

D: 28t^2 – 41tv + 15v^2

User Alhuck
by
5.9k points

1 Answer

5 votes

Answer: Option B is the correct answer

Explanation:

The given expression is

(–7t – 5v)(–4t – 3v).

The product will be a quadratic equation (having 2 as the highest power)

To find the product, we would expand the brackets

(-7t × -4t )+ (-7t × -3v) + (-5v × -4t) + (-5v × - 3v)

= (- -28t^2) +(- -21tv) + (- - 20tv) +(- -15v^2)

Recall, negative × negative equals positive.

=28t^2 +21tv +20tv+ 15v^2)

Collecting like terms, we add all terms containing the same letters together

28t^2 + 41tv + 15v^2

Option B is the correct answer

User MarkusAnd
by
6.4k points