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2Al(s) + Fe2O3(s) → Al2O3(s) + 2Fe(s) T

he ΔHf for Fe2O3(s) = -824.3 kJ/mole.
The ΔHf for Al2O3(s) = -1675.7 kJ/mole.
Finish the equation.
ΔHrxn = [(1) ______ ( kJ/mole) + (2) ______ ( kJ/mole)] - [(1) ______ ( kJ/mole) + (2) ______ ( kJ/mole)]

User Wamiq
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1 Answer

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Answer:

ΔHrxn = [(1) -1675.5 ( kJ/mole) + (2) 0 ( kJ/mole)] - [(1) -824.3 ( kJ/mole) + (2) 0 ( kJ/mole)]

Step-by-step explanation:

ΔHrxn = 2ΔHf (Al₂O₃) - ΔHf (Fe₂O₃)

Remember that for pure elements in their standard state of temperature and pressure by definition their standard heats of formation are zero.

ΔHrxn = 2(-1675.7) - (-824.3) kJ/mol

ΔHrxn = 2527 kJ/mol

User Manas
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