Question

a person pushes a box up a ramp that is 3m long and 1m high. if the box has a mass of 20 kg and the person pushes with a force of 80 N, what is the efficency of the ramp?

Answer 1

Step-by-step explanation:

Efficiency = work out / work in

e = mgh / Fd

e = (20 kg × 9.8 m/s² × 1 m) / (80 N × √(1² + 3²) m)

e ≈ 0.77

Round as needed.

Answer 2

81.67%

Step-by-step explanation:

Efficiency of the ramp
`E= (W_o)/(W_i)`

Work Input
`W_i`= F x s = 80 N x 3 m = 240 J

(F is the force applied and s is the distance moved)

Work Output = m g h (how much the box is lifted above the ground)

m is the mass, g is the acceleration due to gravity and h is the height.

`W_o`= (20 kg)(9.8 m/s²)(1 m) = 196 J

Therefore, efficiency of the ramp is:

`E= (196J)/(240J)= 0.8167`

In percentage, the ramp is 81.67% efficient.