Question

3.) If Lebron James has a vertical leap of +1.35 m. then what is his takeoff speed7 For this

problem, the value of a, = -9.8 m/s2
a.) 5.17 m/s2
b.) 6.9 m/s
c.) 4.3 s
d.) Neither of these choices

Answer 1

D, I hoped that helped you

Answer 2

The answer is 5.14 m/s is the answer. None of the options were correct.

Option: d

Step-by-step explanation:

This is a question of kinematics. In the given question, acceleration
`a=-9.8 \mathrm{m} / \mathrm{s}^(2)`

Vertical loop of James is s = 1.35 m

Final velocity of James is v = 0

We are required to find the take-off speed of James i.e., using the second equation of motion,

v² = u² + 2as

`0-u^(2)=2 *(-9.8) * 1.35`

`-\mathrm{u}^(2)=-19.6 * 1.35`

`\mathrm{u}^(2)=26.46`

u = 5.14 m/s (approx)

So, the answer is none of the choices.