Question

before colliding the momentum of block A is +15.0 kg*m/s, and block B is -35.0 kg*m/s. after, block A has a momentum -12.0 kg*m/s. what is the momentum of block B afterwards?(unit=kg*m/s) remember: right is +, left is - PLEASE HELP ME

Answer 1

The momentum of block B = -8 Kg m/s

Step-by-step explanation:

Given,

The initial momentum of block A, MU = 15 Kg m/s

The initial momentum of block B, mu = -35 Kg m/s

The final momentum of block A, MV = -12 Kg m/s

The final momentum of block B, mv = ?

Consider the block B is initially at rest.

According to the laws of conservation of linear momentum, the momentum of the body before impact is equal to the momentum of the body after impact.

MU + mu = MV + mv

15 + (-35) = (-12) + mv

mv = -20 + 12

= -8 Kg m/s

Hence, the momentum of the block B after impact is, mv = -8 Kg m/s