Question

A 50-g chunk of 80 degrees C iron is dropped into a cavity in a very large block of ice at 0 degrees C. Show that 5.5 g of ice will melt. (The specific heat capacity of iron is 0.11 cal / (g * degree C)).

Answer 1

5.5g of ice melts when a 50g chunk of iron at 80°C is dropped into a cavity

Step-by-step explanation:

The concept to solve this problem is given by Energy Transferred, the equation is given by,

`Q = mc\Delta T`

Where,

Q= Energy transferred

m = mass of water

c = specific heat capacity

`\Delta T =` Temperature change (K or °C)

Replacing the values where mass is 50g and temperature is 80°C to 0°C we have,

`Q = mc\Delta T`

`Q = 50*0.11*(80-0)`

`Q = 440cal`

Then we can calculate the heat absorbed by m grams of ice at 0°C, then

`Q_2 = mL = 80*m`

How Q_1=Q_2, so

`80m=440`

`m=(440)/(80)`

`m = 5.5g`

Then 5.5g of ice melts when a 50g chunk of iron at 80°C is dropped into a cavity