Question

Until a train is a safe distance from the station, it must travel at 5 m/s. Once the train is on open track, it can speed up

to 45 m/s. If it takes a train 8 seconds to reach 45 m/s, what is the acceleration of the train?
m/s4

Answer 1

The acceleration of the train is 5 m/s².

Step-by-step explanation:

Acceleration is the change in velocity over a given time interval.

Therefore, acceleration is given as:

`a=(v_(f)-v_(i))/(\Delta t)`

Where,
`v_(i)\textrm{ and }v_(f)` are initial and final velocities and
`\Delta t` is the time interval.

Here,
`v_(i)=5\textrm{ m/s},v_(f)=45\textrm{ m/s},\Delta t=8\textrm{ s}`

This gives,

`a=(45-5)/(8)=(40)/(8)=5\textrm{ }m/s^(2)`

Therefore, the acceleration of the train is 5 m/s².