Answer:
1.2 × 10^-11 M
Step-by-step explanation:
We are given;
Concentration of Hydrogen ions [H⁺] as 0.00083 M
We are required to calculate the concentration of [OH⁻]
We know that;
pH = - log [H⁺]
POH = -log[OH⁻]
Also, pH + pOH = 14
With the concentration of H⁺ we can calculate the pH
pH = -log 0.00083 M
= 3.08
But; pH + pOH = 14
Therefore; pOH = 14 - pH
= 14 - 3.08
= 10.92
But, pOH = -log[OH⁻]
Therefore; [OH] = -Antilog(pOH)
Hence; [OH⁻] = Antilog -10.92
= 1.2 × 10^-11 M
Therefore, [OH⁻] is 1.2 × 10^-11 M