Answer:
∠ ABC = ∠ ADC proved
Explanation:
Between the triangles Δ BCA and Δ DCA,
(i) CA side is common for both the triangles.
(ii) ∠ ACB = ∠ ACD = 90° {Since Δ BCA and Δ DCA are right triangles}
(iii) Segment BC = Segment CD {Given}
Therefore, from Side-Angle-Side rule Δ BCA ≅ Δ DCA.
Therefore, ∠ ABC = ∠ ADC {Since they are corresponding angles of Δ BCA and Δ DCA. (Proved)