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Find the solution set (x,y,z) of the system:
3x-2y+4z=6
2y-3z=20
6z=12

1 Answer

4 votes

Answer:

The solution is x = 8, y = 13 and z = 2.

Explanation:

We are given a system of equations with the variables x, y, and z from which we have to solve for x, y, and z.

The equations are

3x - 2y + 4z = 6 ........ (1)

2y - 3z = 20 .......... (2)

6z = 12 ......... (3)

Now, from equation (3), we get z = 2.

Now, putting z = 2 in equation (2) we get

2y = 20 + 6 = 26

y = 13

Now, from equation (1), putting y = 13 and z = 2, we get

3x = 6 - (4 × 2) + (2 × 13) = 24

x = 8

So the solution is x = 8, y = 13 and z = 2. (Answer)

User Sarathlal N
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