Question

A 7- kg object is accelerating to the right at 2 km/s^2. What is the magnitude of the rightward net force acting on it?

Answer 1

The magnitude of the rightward net force acting on a 7-kg object with an acceleration of 2 km/s² is 14,000 N.

Step-by-step explanation:

The magnitude of the rightward net force acting on a 7-kg object accelerating to the right at 2 km/s² can be found using Newton's second law of motion. The formula for force is F = ma, where F is the force, m is the mass of the object, and a is the acceleration. In this case, the mass is 7 kg and the acceleration is 2 km/s². Converting the acceleration to meters per second squared, we get 2000 m/s². Plugging these values into the formula,

we get F = (7 kg)(2000 m/s²) = 14,000 N.

Answer 2

Net force is 14 kN.

Step-by-step explanation:

Given:

The mass of the object is,
`m=7\textrm{ kg}`

The acceleration of the object is,
`a=2\textrm{ }km/s^(2)`

According to Newton's second law of motion,

Net force is given as the product of mass and acceleration of the object.

Therefore, the net force acting on the object is given as,

`F=ma\\F=7* 2=14\textrm{ kN}`

Therefore, the magnitude of the rightward net force acting on it is 14 kN.