Question

the temperature of a balloon rises from 275°K to 395°K, what would the ending volume be if it started at 5 L?

Answer 1

7.182 L

Step-by-step explanation:

Concept tested: Charles's law

From the question we are given;

• Initial temeperature, T1 as 275 K
• Initial volume, V1` as 5L
• Final temperature, T2 = 395 K

We are required to calculate the final volume;

• According to Charles's law, the volume of a fixed mass of a gas and its absolute temperature are directly proportional at constant pressure.
• That is;
  `V\alpha T`
• Mathematically,
  `V = kT`, thus,
  `k=(V)/(T)`
• Therefore, at varying temperature and volume;

`(V1)/(T1)=(V2)/(T2)`

Rearranging the formula we can get final volume;

`V2=(V1T2)/(T1)`

`V2=((5L)(395K))/(275)`

`V2=7.182L`

Thus, the ending volume will be 7.182 L