30 Joule of work is to be done.
Option: a
Step-by-step explanation:
Given, mass of snowboard = 5 Kg
Initial speed = 2 m/s, Final speed = 4 m/s, Work done = ΔE
Where, ΔE= change in kinetic energy
Solution:
![\text { Kinetic Energy (initial) }=(1)/(2) * \mathrm{mv}^(2)](https://img.qammunity.org/2020/formulas/physics/middle-school/gioefh5clg2xuwpgu4f40ue0xsz35ywow1.png)
![\text { Kinetic Energy (initial) }=(1)/(2) * 5 \mathrm{Kg} *(2 \mathrm{m} / \mathrm{s})^(2)](https://img.qammunity.org/2020/formulas/physics/middle-school/emmldtp0nlb2vpkk9d2o9axxf8oqrta4jr.png)
=
![\text { Kinetic Energy (final) }=(1)/(2) * m v^(2)](https://img.qammunity.org/2020/formulas/physics/middle-school/72lz2nvgogenbiad2csot1r7w1ojy0qo3u.png)
![(1)/(2) * 5 \mathrm{Kg} *(4 \mathrm{m} / \mathrm{s})^(2)](https://img.qammunity.org/2020/formulas/physics/middle-school/r9epfg7geynxqk06yt0qke4quvilbjb86k.png)
![(1)/(2) * 5 \mathrm{Kg} * 16 \mathrm{m}^(2) / \mathrm{s}^(2)](https://img.qammunity.org/2020/formulas/physics/middle-school/de4bfrsh7lpn2aroz8o3i0ga5ndba7z0ne.png)
![(1)/(2) * 80 \mathrm{Kg} \cdot \mathrm{m}^(2) / \mathrm{s}^(2)](https://img.qammunity.org/2020/formulas/physics/middle-school/42sqpl7ffwr2nued0ycj5y2ofdhla0fjyi.png)
![40 \mathrm{Kg} \cdot \mathrm{m}^(2) / \mathrm{s}^(2)](https://img.qammunity.org/2020/formulas/physics/middle-school/89v2nhi680y7avz81mq0mc4mvbbvjtzs64.png)
Work done = ΔE = Kinetic Energy (final) - Kinetic Energy (initial)
Work done = ΔE = 40 J - 10 J work done = ΔE = 30J