Question

Square coil with l = 0.25 m is placed perpendicularly in a uniform magnetic field that change at a rate of dB/dt = - 0.04 T/s. (a) What is the magnitude of induced emf in the circuit? (b) What is the induced current in the circuit if the coil resistance is 5 ?

Answer 1

The magnitude of induced emf in the circuit is 0.0025 V

the coil resistance is 5 Ω is 0.0005 A

Step-by-step explanation:

The length of coil l = 0.25 m

The flux by Faraday's Law Φ = B A

where

B = magnetic field (T)

A = Area (
`m^(2)`)

induced emf in the circuit (ε)

ε = - dΦ/dt

= - A dB/dt

=
`l^(2)` dB/dt

=
`(0.25)^(2)` (-0.04)

= 0.0025 V

The induced current with 5 Ω of resistance

I = ε/R

where

I = current (A)

R = Resistance (Ω)

thus,

I = (0.0025)/5

= 0.0005 A