Answer:

Step-by-step explanation:
In such a case where the energy stored is in the physical dimension of the material due to the elastic deformation is called the elastic potential energy.
It is mathematically given as:
.....................................[1]
where :
U= elastic potential energy
k= constant of elasticity or the spring constant
= change in the length
Given:
stretch in tendons for the sprinters,
= 41 mm
stretch in tendons for the nonsprinters,
= 33 mm
spring constant for the tendons of both group, k= 31

So, the difference in the stored energy:
![\Delta U=[(1)/(2) k. x_s^2]-[(1)/(2) k. x_n^2]](https://img.qammunity.org/2020/formulas/physics/college/igy86s6mrb9j1xjfxbb5k95hgzlhvptmi8.png)
![\Delta U=(1)/(2) k[ x_s^2-x_n^2]](https://img.qammunity.org/2020/formulas/physics/college/rh9corahvtp69zocj34lkfm951iar2xlab.png)
putting the respective values
![\Delta U=(1)/(2)* 31 * [ 41 ^2-33^2]](https://img.qammunity.org/2020/formulas/physics/college/ny44va4bbxnixbqivlj4kwrxzhrh0vz43j.png)

