Question

In a rock-paper-scissors game, a winner gets 5 points and a loser gets 2 points. After a man played this game 20 times, his total score was 67 points. how many times did he win, and how many times did he lose

Answer 1

The man wins 9 times and looses 11 times in the rock - paper-scissor game.

Explanation:

Let us assume that in the game:

Number of times man wins the games = x times

Number of times man loses the games = y times

Total number of attempts = 20

Points after winning = 5

Points after loosing = 2

Now, according to the question:

x + y =20

and 5 x + 2 y = 67

Now, from (1) y = 20-x, put in (2)

5x + 2y = 67 ⇒ 5x + 2(20 -x) = 67

or, 5x -2x = 67 - 40

or, 3x = 27

⇒ x = 27/3 = 9

then y = 20 - x = 20 - 9 = 11

⇒ x = 9 and y = 11 is the solution of the given system.

Hence, the man wins 9 times and looses 11 times in the rock - paper-scissor game.