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Watch the video that shows using the dilution method to make a solution of known concentration. Note that while the video shows the use of a beaker, in the lab we typically use a volumetric flask to make the diluted solution. The stock solution of KMnO4 has a concentration of 2.6 × 10-4 M. The pipette has a volume of 10.0 mL. What is the amount of KMnO4 delivered to the solution, in moles

1 Answer

1 vote

Answer:


2.6* 10^(-6)\ moles

Step-by-step explanation:

Considering:


Molarity=(Moles\ of\ solute)/(Volume\ of\ the\ solution)

Or,


Moles =Molarity * {Volume\ of\ the\ solution}

Given :

For potassium permanganate :

Molarity =
2.6* 10^(-4)\ M

Volume = 10.0 mL

The conversion of mL to L is shown below:

1 mL = 10⁻³ L

Thus, volume = 10.0×10⁻³ L

Thus, moles of potassium sulfate :


Moles=2.6* 10^(-4) * {10.0* 10^(-3)}\ moles

Moles of potassium permanganate =
2.6* 10^(-6)\ moles

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