Question

Sam, Jimmy, and Andre shared a number of pennies in the ratio 8:5:3. Sam and Andre received a

total of 671 pennies. How many more pennies did Jimmy receive than Andre?

Answer 1

Jimmy received 122 pennies more than Andre

Solution:

Given that , Sam, Jimmy, and Andre shared a number of pennies in the ratio 8:5:3

Sam and Andre received a total of 671 pennies.

Now, let the H.C.F of number of pennies with them be "x"

Then, number of pennies with Sam will be 8x

Number of pennies with Jimmy will be 5x

Number of pennies with Andre will be 3x

Now, we know that, Sam and Andre has a total of 671 pennies

`\begin{array}{l}{\Rightarrow \quad 8 x+3 x=671} \\\\ {\Rightarrow \quad 11 x=671} \\\\ {\Rightarrow \quad x=61}\end{array}`

`\begin{array}{l}{\text { Then, Sam will have } 8 * 61=488 \text { pennies, }} \\\\ {\text { Jimmy will have } 5 * 61=305 \text { pennies, }} \\\\ {\text { Andre will have } 3 * 61=183 \text { pennies. }}\end{array}`

Calculating how many more pennies Jimmy received than Andre:

Number of Pennies Jimmy received more than Andre = Pennies with jimmy - Pennies with Andre

= 305 – 183 = 122

Hence, jimmy has 122 pennies more than Andre