Answer:
Question 6: x = 5/2
Question 7: b= 6
Explanation:
Question 6:
Given that:
-2/5x + 3 = 2/3x + 1/3
Taking variables (terms with x) on left and constants on right side
Signs of transferred terms will be changed
-2/5x -2/3x = 1/3 - 3
Taking LCM on both sides
3/3*-2/5x - 2/3x*5/5 = 1/3 - 3*3/3
-6x/15 -10x/15 = (1-9)/3
-16x/15 = -8/3
Multiplying both sides by -15/16
-16x/15 * -15/16 = -8/3 * -15/16
- "-" sign when multiplied by "-" will give positive
- 3 will be cancelled by 15 giving 5
- 8 will be cancelled by 16 giving 2
x = 5/2
Question 7:
-2.6b + 4 = 0.9b - 17
Taking variables (terms with x) on left and constants on right side
Signs of transferred terms will be changed
-2.6b -0.9b = -17 -4
-3.5b = -21
Dividing both sides by -3.5
b = -21/-3.5
"-" sign will be cancelled out
b = 6
i hope it will help you!