Question

Before colliding, the momentum of block A is -100 kg*m/, and block B is -150 kg*m/s. After, block A has a momentum -200 kg*m/s. What is the momentum of block B afterward? PLEASE HELP

Answer 1

The momentum of block B = -50 Kg m/s

Explanation:

Given,

The initial momentum of block A, MU = -100 Kg m/s

The final momentum of block A, MV = -200 Kg m/s

Consider the block B is initially at rest.

Therefore, the initial momentum of block B, mu = -150 Kg m/s

According to the laws of conservation of linear momentum, the momentum of the body before impact is equal to the momentum of the body after impact.

MU + mu = MV + mv

-100 + (-150) = (-200) + mv

mv = -250 - 200

= -50 Kg m/s

Hence, the momentum of the block B after impact is, mv = -50 Kg m/s