Answer:
The atom of ₄₇Ag¹⁰⁸ have 61 neutrons.
Step-by-step explanation:
The atom of ₄₇Ag¹⁰⁸ have 61 neutrons.
An atom consist of electron, protons and neutrons. Protons and neutrons are present with in nucleus while the electrons are present out side the nucleus.
All these three subatomic particles construct an atom. A neutral atom have equal number of proton and electron. In other words we can say that negative and positive charges are equal in magnitude and cancel the each other. For example if neutral atom has 6 protons than it must have 6 electrons. The sum of neutrons and protons is the mass number of an atom while the number of protons are number of electrons is the atomic number of an atom.
For example in silver atom:
₄₇Ag¹⁰⁸ have 61 neutrons 47 protons and 47 electrons
Mass number = 47+61 = 108
Atomic number = 47