Answer:
deg
m
Step-by-step explanation:
= mass of the heavier truck = 3 tonnes
= velocity of truck before collision =
kmh⁻¹
= mass of lighter truck = 1 tonne
= velocity of lighter truck before collision =
kmh⁻¹
= velocity of combination after collision
Using conservation of momentum



magnitude of the final speed is given as
km/h
Direction is given as
deg
= velocity of combination after collision = 50.31 km/h = 13.98 m/s
= velocity of combination after it comes to stop = 0 m/s
= acceleration =
= -
= - 4.9 m/s²
= stopping distance
using the equation

m