Question

Two positive integers that differ by 9 are in the ratio of 8 to 11. What is the value of the smaller of the two numbers?​

Answer 1

The numbers are 24 and 33 so the smaller one is 24

Answer 2

24 and 33 are the numbers among which 24 is the smallest.

Explanation:

Let one positive integer be x, then another will be x - 9

Solve:

`\sf (x-9 )/(x) = (8)/(11)`

cross multiply

`\sf 11x-99= 8x`

collect like terms

`\sf 11x-8x = 99`

simplify

`\sf 3x = 99`

divide both sides by 3

`\sf x = 33`

As the integer is positive, x = 33, then another will be 33 - 9 = 24.