Question

It is proposed to store 1.00kW⋅h=3.60×106J of electrical energy in a uniform magnetic field with magnitude 0.550 T . What volume (in vacuum) must the magnetic field occupy to store this amount of energy?

Answer 1

`V=29.9\ m^3`

Step-by-step explanation:

Given that,

Magnetic field strength, B = 0.55 T

Energy stored,
`E=3.6* 10^6\ J`

To find,

The magnetic field occupy to store this amount of energy.

Solution,

We know that the magnetic energy per unit volume in the magnetic field is given by :

`(E)/(V)=(B^2)/(2\mu_o)`

`(3.6* 10^6)/(V)=((0.55)^2)/(2* 4\pi * 10^(-7))`

`V=29.9\ m^3`

So, the volume in the vacuum is
`29.9\ m^3`. Hence, this is the required solution.