Final answer:
The molar mass of aluminum trifluoride (AlF3) is calculated by summing the molar mass of one mole of aluminum (26.98 g/mol) with the molar mass of three moles of fluorine (19.00 g/mol each) to get a total of 83.98 g/mol.
Step-by-step explanation:
To calculate the molar mass of aluminum trifluoride, AlF3, we need to sum the molar masses of aluminum (Al) and fluorine (F) with the appropriate number of atoms in the compound. The molar mass of Al is given as 26.98 g/mol, and the molar mass of F is 19.00 g/mol. As there are three atoms of fluorine in aluminum trifluoride, we calculate the molar mass using the following equation:
Molar mass of AlF3 = (1 mol Al × 26.98 g/mol) + (3 mol F × 19.00 g/mol)
Molar mass of AlF3 = 26.98 g/mol + 57.00 g/mol
Molar mass of AlF3 = 83.98 g/mol
This calculated value represents the mass in grams for one mole of aluminum trifluoride.