Question

Please help with this question

Answer 1

`12sin((2\theta))cos((\theta))`

Explanation:

The appropriate trig identity is ...

`sin(a)+sin(b)=2\sin{\left((a+b)/(2)\right)}\cos{\left((a-b)/(2)\right)}`

Here, you have a scale factor of 6 and a=3θ, b=θ. Filling in these values gives ...

`6sin(3\theta)+6sin(\theta)=12\sin{\left((3\theta+\theta)/(2)\right)}\cos{\left((3\theta-\theta)/(2)\right)}\\\\=12sin((2\theta))cos((\theta))`