Question

2. From the top of a vertical cliff 40 m high, the object is 59.3m from the base of the cliff. Find the angle of depression to the objeci. A) 34° B ) 940 C ) 104 degrees D) 540

Answer 1

`34^(\circ)` is the angle of depression from the vertical cliff.

Option: A

Explanation:

Given that, Height of the cliff (opposite side) = 40m

Distance of object from the base of the cliff (adjecent side) = 59.3m

To find the angle of depression of the object. From trigonometric rule in a right angled triangle, we know that
`\tan \theta=\frac{\text { opposite side }}{\text { adjecent side }}`
`\theta=\tan -1 \frac{\text { opposite side }}{\text { adjecent side }}` Angle of depression =
`\tan -1 \frac{\text { height of cliff }}{\text { Distance of object from the base of the cliff }}=\tan ^(-1) (40)/(59.3)=34^(\circ)` Therefore, the angle of depression to the object is
`34^(\circ)`.