Answer:
a) Discrete Uniform Distribution
b) 0.5
c) 0.001
Explanation:
a) What distribution would they use to model the selection?
Since each number has equal probability of being selected, they would be using a Discrete Uniform Distribution.
b) What is the probability the number selected will be an odd number?
Since there are 5,000 odd numbers between 0 and 9999
P(odd)=5,000/10,000 = ½ = 0.5
c) What is the probability the number selected will end in 999?
There are only 10 numbers ending in 999:
0999, 1999, 2999,...,9999
hence
P(number ends in 999)=10/10,000 = 1/1,000 = 0.001