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Write an exponential function in the form y = a that goes through points ( 0 , 13 ) and ( 2 , 637 )

User Mesx
by
6.6k points

1 Answer

6 votes

Answer:


$ y = (13)7^x $

Explanation:

When two points are given say,
$ (x_1, y_1) $ and
$ (x_2, y_2) $ the exponential function passing through these points is given by


$ y = ab^x $

This is obtained by solving for
$ a $ and
$ b $ in


$ y_1 = ab^(x_1) \hspace{15mm} (1) $


$ y_2  = ab^(x_2) \hspace{15mm} (2) $

when we solve (1) and (2) for
$ a $ and
$ b $ we substitute it in the main equation to get the desired exponential function.

Here:
$ (x_1, y_1) = (0, 13) $ and
$ (x_2, y_2) = (2, 637) $.

Substituting in (1) and (2), we get:


$ 13 = ab^0 $


$ 637 = ab^2 $

From the first equation we get:
$ a = 13 $
[since
$ b^0 = 1 $].

Now substitute a = 13 in the second equation to get the value of b.


$ \implies 637 = (13)b^2$


$ \implies b^2 = 49 $
$ \implies b = 7 $

Substituting the values in the main equation we get:


$  y = (13)7^x $

User Plakhoy
by
6.5k points
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