Question

Kramer goes bowling and decides to employ the force of gravity to "pick up a spare." He rolls the 8.00 kg8.00 kg bowling ball very slowly so that it comes to rest a center-to-center distance of 0.200 m0.200 m from the one remaining 2.75 kg2.75 kg bowling pin. Treat both the ball and the pin as point objects, and determine the magnitude of the force of gravity ????⃗ gravF→grav between them.

Answer 1

`F = 3.6* 10^(-8) N`

Step-by-step explanation:

Given data:

mas of bowling ball 8.00 kg

centre to centre distance is 0.200 m

second mass of bowling 2.75 kg

we know that

`F = (GmM)/(D^2)`

Where is G is gravitational constant
`= 6.674* 10^(-11)`

`F = (6.674* 10^(11) * 8 * 2.5)/(0.2^2)`

`F = 3.6* 10^(-8) N`