Help asap please!! I don’t understand

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25 votes

Answer: 2+
(6x-2)/(x(x-3)) ==> x
$\\eq$ 0, x
$\\eq$ 3

Explanation:

f(x)=2x^2-2

g(x)=x^2-3x

(f/g)(x)=

(2x^2-2)/(x^2-3x) =

(2x^2-6x+6x-2)/(x^2-3x) =

2+
(6x-2)/(x^2-3x) =2+
(6x-2)/(x(x-3)) ==> x
$\\eq$ 0, x
$\\eq$ 3

Ergosys answered Jun 11, 2023

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