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Write the equation of a line that is perpendicular to y=7/5x+6 and passes through the point (2, -6)

User Omara
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1 Answer

1 vote

Answer:


y = -(5)/(7)x - 4(4)/(7)

Explanation:

−6 = −5⁄7[2] + b

−1 3⁄7


-4(4)/(7) = b \\ \\ y = -(5)/(7)x - 4(4)/(7)

Perpendicular Lines have OPPOSITE MULTIPLICATIVE INVERSE RATE OF CHANGES [SLOPES], so 1 2⁄5 [or 7⁄5] becomes −5⁄7.

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User Kacper Wiszczuk
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