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Which is the equation of the line that passes through the point (-4,3) and (2,6)

User Hraynaud
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1 Answer

9 votes

Answer:


\displaystyle y = (1)/(2)x + 5

Explanation:

Equation of a Line

The point-slope form of the equation of a line is:

y - k = m ( x - h )

Where m is the slope and (h,k) is a point through which the line passes.

Suppose a line passes through points A(x1,y1) and B(x2,y2). The slope can be calculated with the formula:


\displaystyle m=(y_2-y_1)/(x_2-x_1)

We'll use the points (-4,3) and (2,6), thus:


\displaystyle m=(6-3)/(2+4)=(3)/(6)=(1)/(2)

Now we use the point-slope form using the point (2,6):


\displaystyle y - 6 = (1)/(2)( x - 2 )

Operating:


\displaystyle y - 6 = (1)/(2)x - 1


\displaystyle y = (1)/(2)x - 1 + 6


\boxed{\displaystyle y = (1)/(2)x + 5}

User Shawn Brar
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