Question

the 225-N force is exerted on the crate towards the north and the 165-N is exerted toward the East what’s the magnitude and direction of the net force

Answer 1

force of 279 N

53.75 degrees from east to north

Step-by-step explanation:

let net force be F , Fn - north force , Fe - east force

`F^(2) =F_e^(2) +F_n^(2) \\=225^(2) +165^(2) \\=77850\\\\F=√(77850) \\=279 N`

let the direction be α angle from east to north

`tan( \alpha)=(F_n)/(F_e) =(225)/(165) \\=1.3636\\\\\alpha =tan^(-1) (1.3636)\\=53.75 degrees`